Sqlite3 Tutorial Query Python Fixed Jun 2026

# Create table cursor.execute(''' CREATE TABLE IF NOT EXISTS employees ( id INTEGER PRIMARY KEY, name TEXT NOT NULL, salary REAL ) ''')

# This works because SQLite converts: cursor.execute('SELECT * FROM books WHERE rating = ?', ('4.5',)) # But it's cleaner to use the correct Python type: cursor.execute('SELECT * FROM books WHERE rating = ?', (4.5,))

CREATE TABLE users ( id INTEGER PRIMARY KEY, name TEXT NOT NULL, email TEXT NOT NULL );

print("Database connected successfully!") sqlite3 tutorial query python fixed

# Create products table cursor.execute(''' CREATE TABLE IF NOT EXISTS products ( id INTEGER PRIMARY KEY AUTOINCREMENT, name TEXT NOT NULL, price REAL NOT NULL, stock INTEGER DEFAULT 0 ) ''')

Now, let's connect to the database using Python's sqlite3 module:

You passed an unsupported data type (like a custom object or dictionary). # Create table cursor

conn.close()

The cursor is iterable, which is memory‑efficient:

# Method 1: Fetch all rows def get_all_users(): cursor.execute("SELECT * FROM users") return cursor.fetchall() name TEXT NOT NULL

def get_users_by_age(min_age, limit=10): conn = sqlite3.connect('my_database.db') cursor = conn.cursor()

# Connect to the database conn = sqlite3.connect('example.db') cursor = conn.cursor()

print("\n--- User with ID 1 ---") print(get_user_by_id(1))

If you pass a plain string instead of a tuple to a parameterized query, Python iterates over every character of the string, causing an operational binding error.